MCQ
Product $(A)$ is
- A$H_2C = CH - CH =CH_2$
- ✓$CH_3 - C \equiv C - CH_3$
- C$CH_3 - CH_2 - C \equiv CH$
- D$CH_3 - CH = C = CH_2$
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$2AB_{2(g)} \rightleftharpoons 2AB_{(g)} + B_{2(g)}$
The degree of dissociation is $x$ and is small compared to $1.$ The expression relating the degree of dissociation $(x)$ with equilibrium constant $K_P$ and total pressure $P$ is
$(i)\,\,C\,({\rm{graphite}})\, + \,{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = x\,\,kJ\,mo{l^{ - 1}}$
$(ii)\,\,C\,({\rm{graphite}})\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,CO\,(g);\,\Delta r{H^\circleddash} = y\,\,kJ\,mo{l^{ - 1}}$
$(iii)\,\,CO\,(g)\, + \,\frac{1}{2}{O_2}{\kern 1pt} (g)\, \to \,C{O_2}\,(g);\,\Delta r{H^\circleddash} = z\,\,kJ\,mo{l^{ - 1}}$
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
$C{H_3} - CH(C{H_3}) - C{(C{H_3})_2} - C{H_2} - CH(C{H_3}) - C{H_2} - C{H_3}$
|
|
Primary |
Secondary |
Tertiary |
Quaternary |
|
$(a)$ |
$6$ |
$2$ |
$2$ |
$1$ |
|
$(b)$ |
$2$ |
$6$ |
$3$ |
$0$ |
|
$(c)$ |
$2$ |
$4$ |
$3$ |
$2$ |
|
$(d)$ |
$2$ |
$2$ |
$4$ |
$3$ |