MCQ
Product $(C)$ of this reaction is


- A

- ✓

- C

- D








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${B^{3 + }}_{(aq.)} + 3{e^ - } \to B(s)$ ; $E = 0.6\ Volt$
Using above information find the ion which will be deposited first at cathode if solution containing $A_{(aq.)}^{2 + }$ & $B_{(aq.)}^{ 3+ }$ is electrolysed
${CH}_3-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br} \xrightarrow[\Delta]{\mathrm{KOH}_{(a k)}} \mathrm{A} \xrightarrow{\mathrm{HBr}} \mathrm{B} \xrightarrow[\mathrm{KOH}_{(a) i}]{\Delta} \mathrm{C}$
$(I)\, [Ma_3b_2c]^{n \pm}\,\,\, (II)\, [M(AB)_3]^{n \pm}\,\,\, (III)\, [Ma_2b_2c_2]^{n \pm}$
$(I)\,\,\,-\,\,\,(II)\,\,\,-\,\,\,(III)$