MCQ
Product $(D)$ in above reaction is


- A

- ✓

- C

- D








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$ + \frac{1}{2}\frac{{d\left[ C \right]}}{{dt}} = - \frac{1}{3}\frac{{d\left[ D \right]}}{{dt}} = + \frac{1}{4}\frac{{d\left[ A \right]}}{{dt}} = \frac{{ - d\left[ B \right]}}{{dt}}$
the reaction is

$Z{n^{2 + }} + 2e \to Zn,{E^o} = - 0.762\,V$
$M{g^{2 + }} + 2e \to Mg,{E^o} = - 2.37\,V$
When zinc dust is added to the solution of $MgC{l_2}$
