MCQ
Product $(G)$ is


- A

- B

- ✓

- D








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$P.$ $C{H_3} - CH = C{H_2}\xrightarrow{{HCl}}$
$Q.$ $C{H_3} - CH = C{H_2}\xrightarrow[{{\text{Peroxide}}}]{{HCl}}$
The value of $K _{ C }$ for the following reaction is :
$NH_{3}(g) \rightleftharpoons \frac{1}{2} N _{2}(g)+\frac{3}{2} H_{2}(g)$