MCQ
Product of the reaction is


- AMeso compound
- ✓Enantiomeric pair
- CDiastereomers
- DOptically pure enantiomer


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$\begin{array}{*{20}{c}} {{H_3}C - C{H_2} - CH - Et} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \end{array}$ about $C_2-C_3$ is (figure) 
