MCQ
Product of the reaction is


- A

- B

- ✓Both $(a)$ and $(b)$
- Dnone of these



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Atomic weight : $Fe =55.85 ; \mathrm{S}=32.0$ $\mathrm{O}=16.00$
$\left[\mathrm{CoCl}\left(\mathrm{NH}_3\right)_5\right]^{2+}, \quad\left[\mathrm{Co}(\mathrm{CN})_6\right]^{3-} \text {, }$
$(A)$ $(B)$
$\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{H}_2 \mathrm{O}\right)\right]^{3+}, \quad\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right]^{2+}$
$(C)$ $(D)$
The correct order of $A$, $B$, $C$ and $D$ in terms of wavenumber of light absorbed is :