
- A

- ✓

- C

- D







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End product $(X)$ of the above reaction is
$ArN _{2} Cl \overset{Cu / HCl}{\rightarrow} ArCl + N _{2}$ is known as
$(a)$ ${CrO}_{3}$ $(b)$ ${Fe}_{2} {O}_{3}$ $(c)$ ${MnO}_{2}$ $(d)$ ${V}_{2} {O}_{5}$ $(e)$ ${Cu}_{2} {O}$
$1.$ $\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CHC{H_3}{\mkern 1mu} } \\
{{\mkern 1mu} \,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\,^ + }N{{(C{H_3})}_3}^ - OH}
\end{array}$ $\xrightarrow{{heat}}$ $\mathop {C{H_3}CH = CHC{H_3}}\limits_X $ $+$ $\mathop {C{H_3}C{H_2}CH = C{H_2}}\limits_Y $
$2.$ $\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CHC{H_3}} \\
{\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,Br}
\end{array}$ $\xrightarrow{{heat}}$ $\mathop {C{H_3}CH = CHC{H_3}}\limits_X $ $+$ $\mathop {C{H_3}C{H_2}CH = C{H_2}}\limits_Y $