MCQ
Projection of vector $\vec A$ on $\vec B$ is
- A$\vec A.\vec B$
- ✓$\vec A.\hat B$
- C$\vec B \times \vec A$
- D$\hat B.\hat A$
✓
Answer
Correct option: B.
$\vec A.\hat B$
b
$A\,\cos \,\theta = \frac{{\vec A.\vec B}}{{\left| {\vec B} \right|}} = \vec A.\hat B$
$A\,\cos \,\theta = \frac{{\vec A.\vec B}}{{\left| {\vec B} \right|}} = \vec A.\hat B$
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