MCQ
Propan$-1-$ol can be prepared from propene by alcohol
- A${H_2}O/{H_2}S{O_4}$
- B$Hg{(OAc)_2}/{H_2}O$ followed by $NaB{H_4}$
- ✓${B_2}{H_6}$ followed by ${H_2}{O_2}$
- D$C{H_3}C{O_2}H/{H_2}S{O_4}$
$C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH$
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Glucose, Mannose, Galactose, $\alpha -$ Glucose, $\beta -$ Glucose
$(K)\,\, (L)\,\, (M)\,\, (N)\,\, (O)$
Correct set of epimer and anomer is respectivley
Epimer - Anomer
| List $I$ | List $II$ |
| $A.$ Invertase | $I.$ Starch into maltose |
| $B.$ Zymase | $II.$ Maltose into glucose |
| $C.$ Diastase | $III.$ Glucose into ethanol |
| $D.$ Maltase | $IV.$ Cane sugar into glucose |
Choose the most appropriate answer from the options given below
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,||} \\
{C{H_3} - C - H}
\end{array}$ $\mathop {\xrightarrow{{HCN}}}\limits_{\mathop O\limits^\Theta H} (A)\mathop {\xrightarrow{{{H_2}O/{H^ \oplus }}}}\limits_\Delta $ Product
Product will be :