MCQ
Propan $-1-$ ol can be prepared from propene by
- A$H_2O/H_2SO_4$
- B$Hg(OAc)_2/H_2O$ followed by $NaBH_4$
- ✓$B_2H_6$ followed by $H_2O_2 / OH^\Theta $
- D$CH_3CO_2H/H_2SO_4$
✓
Answer
Correct option: C.
$B_2H_6$ followed by $H_2O_2 / OH^\Theta $
c
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