MCQ
Propanal on treatment with dilute sodium hydroxide forms
- A$CH_3CH_2CH_2CH_2CH_2CHO$
- B$CH_3CH_2CH(OH)CH_2CH_2CHO$
- ✓$CH_3CH_2CH(OH)CH(CH_3)CHO$
- D$CH_3CH_2COONa$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
reagents ' $X$ ' and ' $Y$ ' respectively are:
\end{array}$
Same product $(A)$ will form in both reactions $A$ is
$(I)$ $ZnCl_2$ is ionic whereas $CdCl_2$ and $HgCl_2$ are covalent
$(II)$ $Zn$ and $Cd$ dissolves in dilute acid $(HCl)$ liberating $H_2$ but $Hg$ can not
$(III)$ $Zn$ and $Cd$ forming with ppt. of $Zn(OH)_2$ and $Cd(OH)_2$ but $Hg$ forms coloured ppt. of
$(IV)$ all from $A_2^{2+}$ type ion