- A$Br_2/CCl_4$
- BBaeyer's Reagent
- ✓$AgNO_3 + NH_4OH$
- D$O_3$
$C{H_3} - C \equiv CH\xrightarrow{{AgN{O_3} + N{H_4}OH}}\mathop {C{H_3} - C \equiv \bar C\,Ag}\limits_{white\,ppt} \downarrow $
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(i)$ $\begin{gathered}
HCN\left( {aq} \right) + {H_2}O\left( l \right) \rightleftharpoons {H_3}{O^ + }\left( {aq} \right) + C{N^ - }\left( {aq} \right) \hfill \\
{K_a} = 6.2 \times {10^{ - 10}} \hfill \\
\end{gathered} $
$(ii)$ $\begin{gathered}
C{N^ - }\left( {aq} \right) + {H_2}O\left( l \right) \rightleftharpoons HCN\left( {aq} \right) + O{H^ - }\left( {aq} \right) \hfill \\
{K_b} = 1.6 \times {10^{ - 5}} \hfill \\
\end{gathered} $
These equilibria show the following order of the relative base strength