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STD 11 - 9. Hydricarbon — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 9. Hydricarbon4 Marks
MCQ
Propylene on hydrolysis with sulphuric acid forms
  • A
    $n-$propyl alcohol
  • ✓
    Isopropyl alcohol
  • C
    Ethyl alcohol
  • D
    Butyl alcohol
✓

Answer

Correct option: B.
Isopropyl alcohol
b
(b) $\mathop {C{H_2} = CH - C{H_3} + {H_2}O}\limits_{{\text{Propylene}}} \xrightarrow{{{H_2}S{O_4}}}$   $\mathop {C{H_3} - \mathop {\mathop C\limits^| H}\limits^{OH}  - C{H_3}}\limits_{{\text{Isopropyl alcohol}}} $

Thus in this reaction isopropyl alcohol is formed.

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