Question
Prove that:
$\cos20^\circ\cos40^\circ\cos80^\circ=\frac{1}{8}$
$\cos20^\circ\cos40^\circ\cos80^\circ=\frac{1}{8}$
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$\text{A}\cup(\text{B}-\text{A})=(\text{A}\cup\text{B})$
| column I | column II | ||
| (a) | Throught the point (2, 1) is | (a) | 2x - y = 4 |
| (b) | perpendicular to the line x + 2y + 1 = 0 is | (b) | x + y - 5 = 0 |
| (c) | parpallel to the line 3x + 4y + 5 = 0 | (c) | x - y - 1 |
| (d) | Equally inlined to the axis is | (d) | 3x - 4y - 1 = 0 |