Question
Prove that in an isosceles triangle the altitude from the vertex will bisect the base.
✓
Answer
Now in $\triangle ABD$ and $\triangle ADC$
$AB = AC$
$AD = AD$
$\angle B = \angle C$
Therefore, $\triangle ABD \cong \triangle ADC ...(\text{SSA}$ criteria$)$
Hence, $BD = DC$
Thus, $AD$ bisects $BC.$
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