Question
Prove that $: \sec^245^\circ - \tan^245^\circ = 1$
✓
Answer
$ \text { L.H.S. }=\sec ^2 45^{\circ}-\tan ^2 45^{\circ}$
$ =(\sqrt{2})^2-(1)^2$
$ =2-1$
$ =1$
$ =\text{ R.H.S. }$
$ =(\sqrt{2})^2-(1)^2$
$ =2-1$
$ =1$
$ =\text{ R.H.S. }$
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