Question
Prove that:
$\tan82\frac{1^\circ}{2}=(\sqrt{3}+\sqrt{2})(\sqrt{2}+1)=\sqrt{2}+\sqrt{3}+\sqrt{4}+\sqrt{6}$
$\tan82\frac{1^\circ}{2}=(\sqrt{3}+\sqrt{2})(\sqrt{2}+1)=\sqrt{2}+\sqrt{3}+\sqrt{4}+\sqrt{6}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$8+17+26+\ldots . .+(9 n-1)=\frac{n}{2}(9 n+7)$