Question
Prove that the diagonal elements of a skew symmetric matrix are all zero.

Answer

Let $A$ be a skew-symmetric matrix. Then by definition $A^{\prime}=-A$
 or the $(i, j)^{\text {th }}$ element of $A^{\prime}=$ the $(i, j)^{\text {th }}$ element of $(-A)$
or the $(j, i)^{\text {th }}$ element of $A=-$ the $(i, j)^{\text {th }}$ element of $A$
For the diagonal elements $i=j$ or the $(i, j)$ the element of $A=-$ the $(i, j)^{\text {th }}$ element of $A$
or the $(i, i)^{\text {th }}$ element of $A=0$
Hence the diagonal elements are all zero.

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