Question
Prove that the function f : R → R defined by f (x) = 2x + 5 is one-one.

Answer

Note that a function f is one-one if
f(x1 ) = f (x2 ) $\Rightarrow$ x1 = x2 (definition of one-one function)
Now, given that f (x1 ) = f (x2 ), i.e., 2x1 + 5 = 2x2 + 5
$\Rightarrow$ 2x1 + 5 – 5 = 2x2 + 5 – 5 (adding the same quantity on both sides)
2x1 + 0 = 2x2 + 0
2x1 = 2x2 ( using additive identity of real number)
$\frac{2}{2} x_{1}=\frac{2}{2} x_{2}$ dividing by the same non zero quantity
x1 = x2
Hence, the given function is one one

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