MCQ
Prussian blue is due to the formation of
- ✓$F{e_4}{\left[ {Fe{{(CN)}_6}} \right]_3}$
- B$F{e_2}\left[ {Fe{{(CN)}_6}} \right]$
- C$F{e_3}\left[ {Fe{{(CN)}_6}} \right]$
- D$Fe{\left[ {Fe{{(CN)}_6}} \right]_3}$
✓
Answer
Correct option: A.
$F{e_4}{\left[ {Fe{{(CN)}_6}} \right]_3}$
a
It’s Obvious.
It’s Obvious.
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