MCQ
Quartz is the form ?
- A$ \mathrm{CO}_2$
- ✓$ \mathrm{SiO}_2$
- C$\mathrm{SO}_2 $
- D$ \mathrm{NO}_2 $
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$\begin{gathered}
{\left[ {Al{{\left( {{H_2}O} \right)}_6}} \right]^{ + 3}} + HCO_3^ - \rightleftarrows {\left[ {Al{{\left( {{H_2}O} \right)}_5}OH} \right]^{ + 2}} + {H_2}C{O_3} \hfill \\
\,\,\,\,\,\,\,\,\,\,\,\,(A)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(B)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(C)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(D) \hfill \\
\end{gathered} $
species behaving as bronsted -lowry acid are
Reason : The higher oxidation states for the group $14$ elements are more stable for the heavier members of the group due to ‘inert pair effect’.