Question
Rachel, an engineering student, was asked to make a model shaped like a cylinder with two cones attached at its two ends by using a thin aluminium sheet. The diameter of the model is $3 \ cm$ and its length is $12 \ cm$. If each cone has a height of $2 \ cm$, find the volume of air contained in the model that Rachel made. (Assume the outer and inner dimensions of the model to be nearly the same).

Answer

For upper conical portion
Radius of the base$(r) = 1.5\ cm$
Height $(h_1) = 2 cm$
$\therefore$ Volume $ =\frac13 \pi r^2h_1= \frac13 \pi (1.5)^2(2) = 1.5 \pi\ cm^3$

For lower conical portion
Volume $= 1.5 \pi\ cm^3$
For central cylindrical portion
Radius of the base $(r) = 1.5 cm$
Height $ (h_2) = 12 - (2 + 2) = 12 - 4 = 8 cm$
$\therefore$ Volume $= \pi r^2h_2= \frac13 \pi (1.5)^2(8)= 18 \pi\ cm^3$
Therefore, volume of the model $= 1.5 \pi + 1.5 \pi + 18 \pi = 21 \pi = 21 \times \frac{22}7 = 66\ cm^3$
Hence, the volume of the air contained in the model that Rechel made is $66\ cm^3$.

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