MCQ
Red lead is
- ✓$P{b_3}{O_4}$
- B$PbO$
- C$Pb{O_2}$
- D$P{b_4}{O_3}$
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Given : $K _{ sp } Cu ( OH )_2=1 \times 10^{-20}$
$\operatorname{Take} \frac{2.303 RT }{ F }=0.059 \,V$
The reduction potential at $pH =14$ for the above couple is $(-) x \times 10^{-2}\,V$. The value of $x$ is $........$.