MCQ
Referring to the above two questions, the acceleration due to gravity is given by
- ✓$10 m / sec ^2$
- B$5 m / sec ^2$
- C$20 m / sec ^2$
- D$2.5 m / sec ^2$
✓
Answer
Correct option: A.
$10 m / sec ^2$
(a) $a_x=\frac{d}{d t}\left(v_x\right)=0, a_y=\frac{d}{d t}\left(v_y\right)=-10 m / s ^2$$\therefore$ Net acceleration $a=\sqrt{a_x^2+a_y^2}=\sqrt{0^2+10^2}=10 m / s$
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