Question
Represent a galvanic cell in electrode and ions containing Cu electrode dipped in molar solution of copper sulphate and silver electrode dipped in molar solution of silver nitrate.
$\Big[\text{Given E}^\circ_{\frac{\text{Cu}^{2+}}{\text{Cu(s)}}}=0.34\text{V, E}^\circ_{\frac{\text{Ag}^+}{\text{Ag(s)}}}=0.80\text{V}\Big]$

Answer

Since, the reduction potential of copper is less than that of Ag , so Cu electrode behaves as anode and Ag electrode as cathode,
$\mathrm{Cu}\left|\mathrm{Cu}^{2+}(\mathrm{aq}) \| \mathrm{Ag}^{+}(\mathrm{aq})\right| \mathrm{Ag} .$

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