Question
Represent the following pair of equations graphically and write the coordinates of points where the lines intersects $y-$axis.
$x + 3y = 6,$
$2x - 3y = 12.$

Answer

The given equations are
$x + 3y = 6 ......(i)$
$2x - 3y = 12 ........(ii)$
Putting $x = 0$ in equation $(i)$ we get,
$⇒ 0 + 3y = 6$
$⇒ y = 2$
$⇒ x = 0, y = 2$
Putting $y = 0$ in equation $(i)$ we get,
$⇒ x + 3 × 0 = 6$
$⇒ x = 6$
$⇒ x = 6, y = 0$
Use the following table to draw the graph.
$x$
$0$
$6$
$y$
$2$
$0$
The graph of $(i)$ can be obtained by plotting the two points $A(0, 2), B(6, 0).$
$2x - 3y = 12 ......(ii)$
Putting $x = 0$ in equation $(ii)$ we get,
$⇒ 2 × 0 - 3y = 12$
$⇒ y = -4$
$⇒ x = 0, y = -4$
Putting $y = 0 $ in equation $(ii)$ we get,
$⇒ 2x - 3 × 0 = 12$
$⇒ x = 6$
$⇒ x = 6, y = 0$
Use the following table to draw the graph.
$x$
$0$
$6$
$y$
$-4$
$0$
Draw the graph by plotting two points $C(0, -4), D(6, 0)$ from table.

Graph of lines represented by the equations $x + 3y = 6, 2x - 3y = 12$ meet y-axis at $A(0, 2), C(0, -4)$ respectively.

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