Resistances are arranged in a cyclic order to form a balanced wheatstone bridge as shown in figure. Ratio of power consumed in the branches $P + Q$ and $R + S$ is
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$\frac{{{{\rm{P}}_{\rm{P}}} + {\rm{Q}}}}{{{{\rm{P}}_{\rm{R}}} + {\rm{S}}}} = \frac{{{\rm{R}} + {\rm{S}}}}{{{\rm{P}} + {\rm{Q}}}} = \frac{{\rm{R}}}{{\rm{Q}}}\left( {\frac{{1 + \frac{{\rm{S}}}{{\rm{R}}}}}{{1 + \frac{{\rm{P}}}{{\rm{Q}}}}}} \right) = \frac{{\rm{R}}}{{\rm{Q}}}$
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