Maharashtra BoardEnglish MediumSTD 8MathsFactorization4 Marks
Question
Resolve each of the following quadratic trinomial into factor:
$2 x^2-3 x-2$
✓
Answer
The given expression is $2 x^2-3 x -2$
(Co-efficient of $x^2=2$, co-efficient of $x=-3$ and the constant term $=-2$ )
We will split the co-efficient of $x$ into two number parts such that their sum is -3 and their product equals to the product of the co-efficient of $x ^2$ and constant term, i.e., $2 \times(-2)=-4$
Now,
$(-4)+1=-3 \text { And }(-4) \times 1=-4$
Replacing the middle term 3 x by $-4 x + x$, we have:
$2 x^2-3 x-2=2 x^2-4 x+x-2$
$=\left(2 x^2-4\right)+(x-2)$
$=2 x(x-2)+1(x-2)$
$=(x-2)(2 x+1)$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.