MCQ
$r.m.s.$ velocity of nitrogen molecules at $NTP$ is ...... $m/s$
- A$492$
- ✓$517$
- C$546$
- D$33$
✓
Answer
Correct option: B.
$517$
b
${v_{rms}} = \sqrt {\frac{{3RT}}{M}} = \sqrt {\frac{{3 \times 8.3 \times {{10}^7} \times 300}}{{28}}} $$ = 517m/\sec $
${v_{rms}} = \sqrt {\frac{{3RT}}{M}} = \sqrt {\frac{{3 \times 8.3 \times {{10}^7} \times 300}}{{28}}} $$ = 517m/\sec $
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