MCQ
$s-$character in $sp$ hybridised orbitals are
- A$\frac{1}{3}$
- ✓$\frac{1}{2}$
- C$\frac{1}{4}$
- D$\frac{2}{3}$
$s$-orbitals hold electrons closer to the atom they surround, so a hybridized orbital with $50 \,\%\, s$ character $(sp)$ holds electrons closer because it behaves more like an $s$ atomic orbital.
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$Ag| AgCl | KCl(1\,M) || KBr(1\,M) | AgBr | Ag$
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$[$ Given $: \sqrt{2}=1.41]$