Assertion $A$: Amylose is insoluble in water.

Reason $R$: Amylose is a long linear molecule with more than $200$ glucose units.

In the light of the above statements, choose the correct answer from the options given below.

$(i)$ Glucose $+ ROH \quad \stackrel{\text { dry } HCl }{\longrightarrow}$ Acetal

$\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{x\,eq.of}}$ acetyl derivative

$(ii)$ Glucose $\xrightarrow{{Ni/{H_2}}}A\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{y\,\,eq.\,of}}$ acetyl derivative.

$(iii)$ Glucose $\xrightarrow[{{{\left( {C{H_3}CO} \right)}_2}O}]{{z\,ed.\,of}}$ acetyl derivative.

$' x ^{\prime},{ }^{\prime} y ^{\prime}$ and ${ }^{\prime} z^{\prime}$ in these reactions are respectively.

(Given: specific rotations of ($+$)-sucrose, ($+$)-maltose, $L$-($-$)-glucose anc. $+(+)$-fructose in aqueous solution are $+66^{\circ},+140^{\circ},-52^{\circ}$ and $+92^{\circ}$, respectively)

($A$) 'invert sugar' is prepared by acid catalyzed hydrolysis of maltose

($B$) . 'invert sugar' is an equimolar mixture of $D$-($+$)-glucose and $D$-($-$)-fructose

($C$) specific rotation of 'invert sugar' is $-20^{\circ}$

($D$) on reaction with $\mathrm{Br}_2$ water, 'invert sugar' forms saccharic acid as one of the products