MCQ
Select the correct order of boiling point:
  • A
    diethyl ether $> n-$butyl alcohol $> n-$butaraldehyde $> n-$pentane.
  • $n-$butyl alcohol $> n-$butaraldehyde $> n-$pentane $>$ diethylether.
  • C
    $n-$pentane $> n-$butaraldehyde $> n-$butyl alcohol $>$ diethylether.
  • D
    $n-$butyl alcohol $> n-$butaraldehyde $>$ diethylether $> n-$pentane.

Answer

Correct option: B.
$n-$butyl alcohol $> n-$butaraldehyde $> n-$pentane $>$ diethylether.
As we know that the higher the extent of intermolecular Hydrogen bonding in a molecule, the higher its boiling point becomes.
By that logic$, n-$butyl alcohol will have a higher boiling point than $n-$butyraldehyde due to the presence of more extensive $H-$bonding.
Again, there is no $H-$bonding present in both diethyl ether and $n-$pentane. But as $n-$pentane has a higher molecular weight than that of diethyl ether, it will possess a higher boiling point.

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