- A$C_4H_9 -$ has four alkyl groups
- B$C_5H_{11} -$ has eight alkyl groups
- C$C_3H_7$ has two alkyl groups
- ✓All of these
$C_5H_{11}$ $ \Rightarrow $ $C-C-C-C-C$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|}
\end{array}$ $\begin{array}{*{20}{c}}
{C - C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C - }
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{|\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{ - C - C - C - C}
\end{array}$ $\begin{array}{*{20}{c}}
{C\,\,\,} \\
{|\,\,\,\,} \\
{C - C - C - } \\
{|\,\,\,\,} \\
{\,C\,\,\,\,}
\end{array}\,$ $\begin{array}{*{20}{c}}
{C\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C - C - C - C} \\
{\,\,\,\,\,\,\,\,\,\,|}
\end{array}$
$C_3H_7$ $ \Rightarrow $ $C-C-C-$ $\begin{array}{*{20}{c}}
{C - C - C} \\
|
\end{array}$
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Reason : $sp$ hybridised carbon atoms of acetylene are considerably electronegative.
Calculate $\Delta {T_b}$ if ${K_f} = 1.86$ and ${K_b} = 0.521$.
(Round off to the Nearest Integer).
[Given : Henry's law constant $= K _{ H }=8.0 \times 10^{4} kPa$ for $O _{2}$ Density of water with dissolved oxygen $=1.0\, kg\, dm ^{-3}$ ]