- ✓$Z = 12, 38, 4, 88$
- B$Z = 9, 16, 3, 35$
- C$Z = 5, 11, 27, 19$
- D$Z = 24, 47, 42, 55$
because every period is having certain intervals such as 2,8,8,18,18,32,31 to 1 to 7 periods respectively.
so that if we add these numbers to element atomic number we can get next element of the same group.a)
$4,4+8,12+8,20+18,38+18,56+32$
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$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[{{\text{H}}_{2}}{{\text{O}}_{2}},\bar{O}\text{H}]{\text{B}{{\text{H}}_{3}},\text{THF}}(P)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(Q)$
$\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}$ $\xrightarrow[NaB{{H}_{4}}\,,\,H{{O}^{\Theta }}]{Hg\,{{(OAc)}_{2}}\,,\,{{H}_{2}}O}(R)$ $\xrightarrow[\text{C}{{\text{H}}_{2}}\text{C}{{\text{l}}_{2}}]{\text{ Pyridinium Chloro Chromate }(\text{PCC})}$ $(S)$
