- ✓$Z = 12, 38, 4, 88$
- B$Z = 9, 16, 3, 35$
- C$Z = 5, 11, 27, 19$
- D$Z = 24, 47, 42, 55$
because every period is having certain intervals such as 2,8,8,18,18,32,31 to 1 to 7 periods respectively.
so that if we add these numbers to element atomic number we can get next element of the same group.a)
$4,4+8,12+8,20+18,38+18,56+32$
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(Critical micelle concentration ($CMC$) is marked with an arrow in the figures.)
$X_2O_4(g) \to 2XO_2(g)$
$\Delta U = 2.1\, kcal, \Delta S = 20\, cal\, K^{-1}$ at $300\, K$.
Hence $\Delta G$ is ....$kcal$

Given, $\lambda_{\left(\mathrm{Ag}^{+}\right)}^{\circ}=6 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}, \lambda_{\left(\mathrm{Br}^{-}\right)}^{\circ}=8 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}, \lambda_{\left(\mathrm{NO}_{\mathrm{j}}\right)}^{\circ}=7 \times 10^{-3} \mathrm{Sm}^2 \mathrm{~mol}^{-1}$.