Question
Short-Answer Question:
Write the zeros of the quadratic polynomial $f(x) = 6x^2- 3$
Write the zeros of the quadratic polynomial $f(x) = 6x^2- 3$
✓
Answer
To find the zeros of the quadratic polynomial we will equate $f(x)$ to $0$
$ f(x)=0 $
$ \Rightarrow 6 x^2-3=0 $
$ \Rightarrow 3\left(2 x^2-1\right)=0 $
$ \Rightarrow 2 x^2-1=0 $
$ \Rightarrow 2 x^2=1$
$\Rightarrow\text{x}^2=\frac{1}{2}$
$\Rightarrow\text{x}=\pm\frac{1}{\sqrt2}$
Hence, the zeros of the quadratic polynomial $f(x) = 6x^2- 3$ are $\frac{1}{\sqrt2},\ -\frac{1}{\sqrt2}.$
$ f(x)=0 $
$ \Rightarrow 6 x^2-3=0 $
$ \Rightarrow 3\left(2 x^2-1\right)=0 $
$ \Rightarrow 2 x^2-1=0 $
$ \Rightarrow 2 x^2=1$
$\Rightarrow\text{x}^2=\frac{1}{2}$
$\Rightarrow\text{x}=\pm\frac{1}{\sqrt2}$
Hence, the zeros of the quadratic polynomial $f(x) = 6x^2- 3$ are $\frac{1}{\sqrt2},\ -\frac{1}{\sqrt2}.$
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