Question
Show that : $\sin ^{-1}\left(\frac{5}{13}\right)+\cos ^{-1}\left(\frac{3}{5}\right)=\tan ^{-1}\left(\frac{63}{16}\right)$
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$\frac{\cos ^2 y}{x} d y+\frac{\cos ^2 x}{y} d x=0$
$\left(x-y^2 x\right) d x-\left(y+x^2 y\right) d y=0$, when $x=2, y=0$
| Differential equation | Function |
| $\text{x}+\text{y}\frac{\text{dy}}{\text{dx}}=0$ | $\text{y}=\pm\sqrt{\text{a}^2-\text{x}^2}$ |