Question
Show that the function $f(x)=x^3-3 x^2+6 x-100$ is increasing on R.

Answer

$f(x)=x^3-3 x^2+6 x-100$
$f^{\prime}(x)=3 x^2-6 x+6$
$=3\left[x^2-2 x+2\right]=3\left[(x-1)^2+1\right]$
since $f^{\prime}(x)>0 ; x \in R$
$\therefore f(x)$ is increasing on $R$.

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