Question
Show that the function given by $f\left( x \right) = {e^{2x}}$ is increasing on R.
$\therefore f'\left( x \right) = {e^{2x}}\frac{d}{{dx}}(2x) = {e^{2x}}\left( 2 \right) = 2{e^{2x}} > 0$ i.e., positive for all $x \in R$
Therefore, f(x) is strictly increasing on R.
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$\text{X}$
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$0$
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$1$
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$2$
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$3$
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$\text{P}(\text{X})$
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$\text{k}$
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$\frac{\text{k}}{2}$
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$\frac{\text{k}}{4}$
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$\frac{\text{k}}{8}$
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