Question
Show that $x = -2$ is a solution of $3 x^2+13 x+14=0$.
✓
Answer
Given equation is $3 x^2+13 x+14=0$
Substituting $x = -2$ in $L.H.S$. of above equation, we get
$L.H.S.$ $= 3(-2)^2+ 13 × (-2) + 14$
$= 12 - 26 + 14$
$= 26 - 26$
$= 0$
$= R.H.S.$
Hence, $x = -2$ is a solution of the given equation.
Substituting $x = -2$ in $L.H.S$. of above equation, we get
$L.H.S.$ $= 3(-2)^2+ 13 × (-2) + 14$
$= 12 - 26 + 14$
$= 26 - 26$
$= 0$
$= R.H.S.$
Hence, $x = -2$ is a solution of the given equation.
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