Question
Show the following quadratic equation by factorization method:
$13x^2 - 7x + 1 = 0$
$13x^2 - 7x + 1 = 0$
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$(a+b)^2+\left(a \omega+b \omega^2\right)^2+\left(a \omega^2+b \omega\right)^2=6 a b$