Question
Show the following quadratic equation by factorization method:
$\text{x}^2+\text{x}+\frac{1}{\sqrt{2}}=0$
$\text{x}^2+\text{x}+\frac{1}{\sqrt{2}}=0$
$= 1 - 2\sqrt{2}$
From (A) $\text{x}=\frac{-1\pm\sqrt{-(2\sqrt{2}-1})}{2}$ $=\frac{-1\pm\sqrt{2\sqrt{2}-1\text{ i}}}{2}$ Thus, $\therefore\text{x}=\frac{-1\pm\sqrt{2\sqrt{2}-1\text{ i}}}{2}$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Using binomial theorem write down the expansions of the following:
$(^3\sqrt{\text{x}}-^3\sqrt{\text{a}})^6$
$0.\overline{3}$
$\tan{\text{(A - B)}}$