Question
Show the following quadratic equation:
ix2 - x + 12i = 0
ix2 - x + 12i = 0
✓
Answer
We will apply discriminate rule on ax2 + bx + c = 0
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{b}^2-4\text{ac}}}{2\text{a}}$
Now,
ix2 - x + 12i = 0
$\text{x}=\frac{-(-1)\pm\sqrt{(-1)^2-4(\text{i)}(12\text{i}})}{2\text{i}}$
$=\frac{1\pm\sqrt{1+48}}{2\text{i}}$
$=\frac{1\pm\sqrt{49}}{2\text{i}}$
$=\frac{1\pm7}{2\text{i}}$
$=\frac{8}{2\text{i}},\frac{-6}{2\text{i}}$
$=\frac{4}{\text{i}},-\frac{3}{\text{i}}$
$=-4\text{i},3\text{i}$
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{b}^2-4\text{ac}}}{2\text{a}}$
Now,
ix2 - x + 12i = 0
$\text{x}=\frac{-(-1)\pm\sqrt{(-1)^2-4(\text{i)}(12\text{i}})}{2\text{i}}$
$=\frac{1\pm\sqrt{1+48}}{2\text{i}}$
$=\frac{1\pm\sqrt{49}}{2\text{i}}$
$=\frac{1\pm7}{2\text{i}}$
$=\frac{8}{2\text{i}},\frac{-6}{2\text{i}}$
$=\frac{4}{\text{i}},-\frac{3}{\text{i}}$
$=-4\text{i},3\text{i}$
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