MCQ
શ્રેણિક $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\{ - 4}&2\end{array}} \right]$ નો વ્યસ્ત મેળવો.
  • $\frac{{ - 1}}{8}\,\left[ {\begin{array}{*{20}{c}}2&3\\4&2\end{array}} \right]$
  • B
    $\frac{{ - 1}}{8}\,\left[ {\begin{array}{*{20}{c}}3&2\\2&4\end{array}} \right]$
  • C
    $\frac{1}{8}\,\left[ {\begin{array}{*{20}{c}}2&3\\4&2\end{array}} \right]$
  • D
    $\frac{1}{8}\,\left[ {\begin{array}{*{20}{c}}3&2\\2&4\end{array}} \right]$

Answer

Correct option: A.
$\frac{{ - 1}}{8}\,\left[ {\begin{array}{*{20}{c}}2&3\\4&2\end{array}} \right]$
Let $A = \left[ {\begin{array}{*{20}{c}}2&{ - 3}\\{ - 4}&2\end{array}} \right]\,$
${\rm{ }}\therefore \,|A|\, = \,\left| {\,\begin{array}{*{20}{c}}2&{ - 3}\\{ - 4}&2\end{array}\,} \right| = 4 - 12 = - 8$ The matrix of cofactors of the elements of  $A $ viz.
$\left[ {\begin{array}{*{20}{c}}{{c_{11}}}&{{c_{12}}}\\{{c_{21}}}&{{c_{22}}}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}2&{ - ( - 4)}\\{ - ( - 3)}&2\end{array}} \right] = \left[ {\,\begin{array}{*{20}{c}}2&4\\3&2\end{array}\,} \right]$
$\therefore \text{adj}\ A = $ transpose of the matrix of cofactors of elements of $A = \left[ {\begin{array}{*{20}{c}}2&3\\4&2\end{array}} \right]$ 
${A^{ - 1}} = \frac{1}{\Delta }(\text{adj}\ \,A) = \frac{1}{{ - 8}}\,\left[ {\begin{array}{*{20}{c}} 2&3 \\  4&2  \end{array}} \right]$

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