- Asilica
- ✓silicic acid
- Csilicone
- Dsilicate
The reaction is as follows:
$\mathrm{SiCl}_{4}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Si}(\mathrm{OH})_{4}+4 \mathrm{HCl}$
Hence, silicic acid is formed when $\mathrm{SiCl}_{4}$ undergoes hydrolysis.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$\left[\mathrm{PtCl}_{4}\right]^{2-}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons\left[\mathrm{Pt}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{3}\right]^{-}+\mathrm{Cl}^{-}$
was measured as a function of concentrations of different species. It was observed that
$\frac{-\mathrm{d}\left[\left[\mathrm{PtCl}_{4}\right]^{2-}\right]}{\mathrm{dt}}=4.8 \times 10^{-5}\left[\left[\mathrm{PtCl}_{4}\right]^{2-}\right]-2.4 \times10^{-3}\left[\left[\mathrm{Pt}\left(\mathrm{H}_{2} \mathrm{O}\right) \mathrm{Cl}_{3}\right]^{-}\right]\left[\mathrm{Cl}^{-}\right]$
where square brackets are used to denote molar concentrations. The equilibrium constant $\mathrm{K}_{\mathrm{c}}=....$. (Nearest integer)