- Asilica
- ✓silicic acid
- Csilicone
- Dsilicate
The reaction is as follows:
$\mathrm{SiCl}_{4}+4 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{Si}(\mathrm{OH})_{4}+4 \mathrm{HCl}$
Hence, silicic acid is formed when $\mathrm{SiCl}_{4}$ undergoes hydrolysis.
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$ \text { a } \mathrm{Cl}_2(\mathrm{~g})+\mathrm{b} \mathrm{OH}^{-}(\mathrm{aq}) \rightarrow \mathrm{c} \mathrm{ClO}^{-}(\mathrm{aq})+\mathrm{d} \mathrm{Cl}^{-}(\mathrm{aq}) +\mathrm{e} \mathrm{H}_2 \mathrm{O}(l)$
The values of $a, \ b,\ c$ and $d$ in a balanced redox reaction are respectively :

$(I)$ $I.P.$ of $O(g)$ is less than $I.P.$ of $O_{\left( g \right)}^ - $
$(II)$ $I.P.$ of $Ne(g)$ is greater than $I.P$. of $Ne_{\left( g \right)}^ + $
$(III)$ $E.A.$ of $O_{\left( g \right)}^ + $ is greater than $E.A.$ of $O(g)$
$(IV)$ $I.P.$ of $N(g)$ is greater than $I.P.$ of $N_{\left( g \right)}^ + $
