- AWater
- BConc. $HCl$
- ✓$NH_4OH$
- D$CCl_4$
It dissolves in $NH_4OH$ solution due to the formation of complex salt.
$AgCl + 2N{H_4}OH \to \mathop {[Ag{{(N{H_3})}_2}]Cl + 2{H_2}O}\limits_{{\text{Diamminesilver (I) chloride}}} $
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$(I)\,\,q + \mathrm{w}$ $(II)\,\, q$
$(III)\,\, \mathrm{w}$ $(IV)\,\, H - TS$
$(a)\, \Delta U = 0$
$(b)\, q = 0$
$(c)\, \Delta T = 0$
$(d)\,q = 2.303\,nRT\,{\log _{10}}\,\left( {\frac{{{V_2}}}{{{V_1}}}} \right)$

$Pt _{( s )}\left| H _2( g , 1\,atm )\right| H ^{+}( aq , 1 M )|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid Pt ( s )$
When the potential of the cell is $0.712\,V$ at $298\,K$, the ratio $\left[ Fe ^{2+}\right] /\left[ Fe ^{3+}\right]$ is $.......$(Nearest integer)
Given: $Fe ^{3+}+ e ^{-}= Fe ^{2+}, E ^{\circ} Fe ^{3+}, Fe ^{2+} \mid Pt =0.771$
$\frac{2.303 RT }{ F }=0.06\,V$