Question
Silver crystallises with face-centred cubic unit cells. Each side of the unit cell has a length of 409 pm. What is the radius of an atom of silver? (Assume that each face atom is touching the four corner atoms.)

Answer

For fcc unit cell
$\text{r}=\frac{\text{d}}{2}=\frac{\text{a}}{2\sqrt{2}}$
Given a = 409 pm
∴ r = 409/2√2
r = 144.62 pm.

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