- ✓$AgBr\, (K_{sp} = 5 \times 10^{-13})$
- B$AgCl\, (K_{sp} = 1.8 \times 10^{-10})$
- C$Ag_2CO_3\, (K_{sp} = 8.1 \times 10^{-12})$
- D$Ag_3AsO_4\, (K_{sp} = 1 \times 10^{-22})$
$\mathrm{AgCl} ;\left[\mathrm{Ag}^{+}\right]=\frac{1.8 \times 10^{-10}}{0.1}=1.8 \times 10^{-9}\, \mathrm{M}$
$\mathrm{Ag}_{2} \mathrm{CO}_{3}:\left[\mathrm{Ag}^{+}\right]^{2}=\frac{8.1 \times 10^{-12}}{0.1} ;\left[\mathrm{Ag}^{+}\right]=9 \times 10^{-6}\, \mathrm{M}$
$\mathrm{Ag}_{3} \mathrm{AsO}_{4} ;\left[\mathrm{Ag}^{+}\right]^{3}=\frac{1 \times 10^{-22}}{0.1}:\left[\mathrm{Ag}^{+}\right]=10^{-7} \,\mathrm{M}$
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$\begin{array}{*{20}{c}}
H\\
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{ClHC = HC - C - CH = CHCl}\\
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{Cl}
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(Given: Atomic no. $Eu, 63; Sm , 62 ; Tm , 69 ; Tb$, $65 ; Yb , 70 ; Dy , 66]$
(Consider heat capacity of all solutions as $4.2 J g ^{-1} K ^{-1}$ and density of all solutions as $1.0 \ g mL ^{-1}$ )
$1.$ Enthalpy of dissociation (in $kJ mol ^{-1}$ ) of acetic acid obtained from the Expt. $2$ is
$(A)$ $1.0$ $(B)$ $10.0$ $(C)$ $24.5$ $(D)$ $51.4$
$2.$ The $pH$ of the solution after Expt. $2$ is
$(A)$ $2.8$ $(B)$ $4.7$ $(C)$ $5.0$ $(D)$ $7.0$
Give the answer question $1$ and $2.$