Question
Simplify : $1 \frac{1}{2} \times 2 \frac{3}{4} \div 1 \frac{4}{7}$ of $2 \frac{5}{8}$
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Answer
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Find each angle shown in the diagram.
Radhika is in the Chemistry Laboratory and is working on a practical. She mixed three salts A, B and C taking 150 gm of A and 300 gm each of B and C to prepare a mixture X.
Q.1. The percentage of salt A in mixture X is:
(a) 15% $\quad$$\quad$(b) 20% $\quad$$\quad$(c) 25%$\quad$$\quad$ (d) 30%
Q.2. By what percent is salt C more than salt A in mixture X?
(a) 50% $\quad$$\quad$(b) 100%$\quad$$\quad$ (c) 150% $\quad$$\quad$(d) 200%
Q.3. Radhika added 250 gm of salt B to mixture X to prepare a new mixture Y. By what per cent did salt B increase
(a) $63 \frac{1}{3} \%$$\quad$$\quad$ (b) $75 \%$ $\quad$$\quad$(c) $83 \frac{1}{3} \%$ $\quad$$\quad$(d) $121 \%$
Q.4. The percentage of salt A in mixture Y is :
(a) $15 \%$ $\quad$$\quad$(b) $17 \frac{1}{2} \%$ $\quad$$\quad$(c) $20 \%$$\quad$$\quad$ (d) $22 \frac{1}{2} \%$
→Q.1. The percentage of salt A in mixture X is:
(a) 15% $\quad$$\quad$(b) 20% $\quad$$\quad$(c) 25%$\quad$$\quad$ (d) 30%
Q.2. By what percent is salt C more than salt A in mixture X?
(a) 50% $\quad$$\quad$(b) 100%$\quad$$\quad$ (c) 150% $\quad$$\quad$(d) 200%
Q.3. Radhika added 250 gm of salt B to mixture X to prepare a new mixture Y. By what per cent did salt B increase
(a) $63 \frac{1}{3} \%$$\quad$$\quad$ (b) $75 \%$ $\quad$$\quad$(c) $83 \frac{1}{3} \%$ $\quad$$\quad$(d) $121 \%$
Q.4. The percentage of salt A in mixture Y is :
(a) $15 \%$ $\quad$$\quad$(b) $17 \frac{1}{2} \%$ $\quad$$\quad$(c) $20 \%$$\quad$$\quad$ (d) $22 \frac{1}{2} \%$
Oranges are bought at 100 for ?80 and all of them are sold at ₹80 for ₹100. Find the loss or gain as percent in this transaction.
Express the following in exponential form: $3600$
→Ram Nath sold one of his properties worth ₹ 38,00,000. He wished to divide this money between his two daughters Priya and Seema in the ratio $7: 12$. He sold another property for ₹ 60,00,000. He divided this money between Priya and Seema in the ratio $\frac{1}{5}: \frac{1}{7}$.
Q.1. What amount did Priya receive from the sale of second property?
(a) ₹ 14,00,000 $\quad$$\quad$(b) ₹ 24,00,000$\quad$$\quad$ (c) ₹ 25,00,000 $\quad$$\quad$(d) ₹ 35,00,000
Q.2. What amount did Seema receive from the sale of first property?
(a) ₹ 14,00,000 $\quad$$\quad$(b) ₹ 24,00,000$\quad$$\quad$ (c) ₹ 25,00,000$\quad$$\quad$ (d) ₹ 49,00,000
Q.3. The difference between the total amounts received by Priya and Seema is:
(a) ₹ 0 $\quad$$\quad$(b) ₹ 1,00,000 $\quad$$\quad$(c) ₹ 2,00,000 $\quad$$\quad$(d) ₹ 5,00,000
Q.4. The ratio between the amounts received by Seema from the sale of the first and the second properties is :
(a) $1: 1$$\quad$$\quad$ (b) $12: 7$$\quad$$\quad$ (c) $24: 25$ $\quad$$\quad$(d) $14: 35$
→Q.1. What amount did Priya receive from the sale of second property?
(a) ₹ 14,00,000 $\quad$$\quad$(b) ₹ 24,00,000$\quad$$\quad$ (c) ₹ 25,00,000 $\quad$$\quad$(d) ₹ 35,00,000
Q.2. What amount did Seema receive from the sale of first property?
(a) ₹ 14,00,000 $\quad$$\quad$(b) ₹ 24,00,000$\quad$$\quad$ (c) ₹ 25,00,000$\quad$$\quad$ (d) ₹ 49,00,000
Q.3. The difference between the total amounts received by Priya and Seema is:
(a) ₹ 0 $\quad$$\quad$(b) ₹ 1,00,000 $\quad$$\quad$(c) ₹ 2,00,000 $\quad$$\quad$(d) ₹ 5,00,000
Q.4. The ratio between the amounts received by Seema from the sale of the first and the second properties is :
(a) $1: 1$$\quad$$\quad$ (b) $12: 7$$\quad$$\quad$ (c) $24: 25$ $\quad$$\quad$(d) $14: 35$
Arrange the given rational numbers in ascending order:
$\frac{7}{10}, \frac{-11}{-30} \text { and } \frac{5}{-15}$
→$\frac{7}{10}, \frac{-11}{-30} \text { and } \frac{5}{-15}$
Apply the properties of isosceles and equilateral triangles to find the unknown angles in the given figure:
In the given figure, we have $P Q=S R$ and $P R=S Q$.
Prove that :
(i) $\triangle PQR \cong \triangle SRQ$
(ii) $\angle PQR =\angle SRQ$
→Prove that :
(i) $\triangle PQR \cong \triangle SRQ$
(ii) $\angle PQR =\angle SRQ$
Simplify: $\mathrm{p}^2-\left[\mathrm{x}^2-\left\{\mathrm{x}^2-\left(\mathrm{q}^2-\overline{\mathrm{x}^2-\mathrm{q}^2}\right)-2 \mathrm{y}^2\right\}\right]$
→Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
AB = AC = 6.5 cm and ∠A = 60°